Knowing
how much dust will be collected in a dust collection system is very important.
The method below is what is as good as any:
Let’s
use the example of an 18-bag dust collector on typical woodworking dust from
two table saws. We expect a large portion of the dust to be sawdust.
Each
table saw requires about 660 CFM, therefore we need 1320 CFM at the dust
collector.
Assume
a loading of 10 grains per cu.ft. (from experience; woodworking is 10-20
grains, Material handling transfer points is 3-5 grains, fumes is 10grains per
1000 cu.ft.)
1320
CFM x 10 grains = 13200 grains/min
13200
/ 7000 grains/lb = 1.89 lbs/min x 60 min = 113 lbs/hour
A
55 (45 imperial) gallon drum is 9 cu.ft. volume.
From
a dust collection selection chart, density of wood is 10-30 lbs/cu.ft.
Therefore,
a drum will hold 20 lbs/cu.ft. x 9 cu.ft = 180 lbs/drum
We
will fill 113 lbs/hour / 180 lbs/drum = 5 drums per 8 hour shift.
For assistance with: dust collection applications and troubleshooting
